3^2x+1=7^x-2

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Solution for 3^2x+1=7^x-2 equation: 



3^2x+1=7^x-2

We move all terms to the left:

3^2x+1-(7^x-2)=0

We get rid of parentheses

3^2x-7^x+2+1=0

We add all the numbers together, and all the variables

3^2x-7^x+3=0

We move all terms containing x to the left, all other terms to the right

3^2x-7^x=-3

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